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1\chapter{C Enumeration in \texorpdfstring{\CFA}{Cforall}}
2
3\CFA supports legacy C enumeration using the same syntax for backward compatibility.
4A C-style enumeration in \CFA is called a \newterm{C Enum}.
5The semantics of the C Enum is mostly consistent with C with some restrictions.
6The following sections detail all of my new contributions to enumerations in C.
7
8
9\section{Visibility}
10\label{s:CVisibility}
11
12In C, unscoped enumerators present a \newterm{naming problem} when multiple enumeration types appear in the same scope with duplicate enumerator names.
13\begin{cfa}
14enum E1 { First, Second, Third, Fourth };
15enum E2 { @Fourth@, @Third@, @Second@, @First@ }; $\C{// same enumerator names}$
16\end{cfa}
17There is no mechanism in C to resolve these naming conflicts other than renaming one of the duplicates, which may be impossible if the conflict comes from system include-files.
18
19The \CFA type-system allows extensive overloading, including enumerators.
20Hence, most ambiguities among C enumerators are implicitly resolved by the \CFA type system, possibly without any programmer knowledge of the conflict.
21In addition, C Enum qualification is added, exactly like aggregate field-qualification, to disambiguate.
22\VRef[Figure]{f:EnumeratorVisibility} shows how resolution, qualification, and casting are used to disambiguate situations for enumerations @E1@ and @E2@.
23
24\begin{figure}
25\begin{cfa}
26E1 f() { return Third; }                                $\C{// overload functions with different return types}$
27E2 f() { return Fourth; }
28void g( E1 e );
29void h( E2 e );
30void foo() {                                                    $\C{// different resolutions and dealing with ambiguities}$
31        E1 e1 = First;   E2 e2 = First;         $\C{// initialization}$
32        e1 = Second;   e2 = Second;                     $\C{// assignment}$
33        e1 = f();   e2 = f();                           $\C{// function return}$
34        g( First );   h( First );                       $\C{// function argument}$
35        int i = @E1.@First + @E2.@First;        $\C{// disambiguate with qualification}$
36        int j = @(E1)@First + @(E2)@First;      $\C{// disambiguate with cast}$
37}
38\end{cfa}
39\caption{Enumerator Visibility and Disambiguating}
40\label{f:EnumeratorVisibility}
41\end{figure}
42
43
44\section{Scoping}
45
46A C Enum can be scoped, using @'!'@, so the enumerator constants are not projected into the enclosing scope.
47\begin{cfa}
48enum Week @!@ { Mon, Tue, Wed, Thu = 10, Fri, Sat, Sun };
49enum RGB @!@ { Red, Green, Blue };
50\end{cfa}
51Now the enumerators \emph{must} be qualified with the associated enumeration type.
52\begin{cfa}
53Week week = @Week.@Mon;
54week = @Week.@Sat;
55RGB rgb = @RGB.@Red;
56rgb = @RGB.@Blue;
57\end{cfa}
58% with feature unimplemented
59It is possible to toggle back to unscoped using the \CFA @with@ auto-qualification clause/statement (see also \CC \lstinline[language=c++]{using enum} in Section~\ref{s:C++RelatedWork}).
60\begin{cfa}
61with ( @Week@, @RGB@ ) {                                $\C{// type names}$
62         week = @Sun@;                                          $\C{// no qualification}$
63         rgb = @Green@;
64}
65\end{cfa}
66As in Section~\ref{s:CVisibility}, opening multiple scoped enumerations in a @with@ can result in duplicate enumeration names, but \CFA implicit type resolution and explicit qualification/casting handle this localized scenario.
67
68
69\section{Type Safety}
70\label{s:TypeSafety}
71
72As in Section~\ref{s:Usage}, C's implicit bidirectional conversion between enumeration and integral type raises a safety concern.
73In \CFA, the conversion is changed to unidirectional: an enumeration can be implicitly converted into an integral type, with an associated @safe@ conversion cost.
74However, an integral type cannot be implicitly converted into a C enumeration because the conversion cost is set to @infinity@.
75\begin{cfa}
76enum Bird { Penguin, Robin, Eagle };
77enum Fish { Shark, Salmon, Whale };
78
79int i = Robin;                                                  $\C{// allow, implicitly converts to 1}$
80enum Bird @bird = 1;@                                   $\C{// disallow }$
81enum Bird @bird = Shark;@                               $\C{// disallow }$
82\end{cfa}
83It is now up to the programmer to insert an explicit cast to force the assignment.
84\begin{cfa}
85enum Bird bird = @(Bird)@1;
86enum Bird bird = @(Bird)@Shark
87\end{cfa}
88
89Note, \CC has the same safe restriction~\cite[C.1.5.7.2]{C++} and provides the same workaround cast.
90\begin{description}[parsep=0pt]
91\item[Change:] \CC objects of enumeration type can only be assigned values of the same enumeration type.
92In C, objects of enumeration type can be assigned values of any integral type.
93Example:
94\begin{cfa}
95enum color { red, blue, green };
96color c = 1;                            $\C{// valid C, invalid \CC}$
97\end{cfa}
98\item[Rationale:] The type-safe nature of \CC.
99\item[Effect on original feature:] Deletion of semantically well-defined feature.
100\item[Difficulty of converting:] Syntactic transformation. (The type error produced by the assignment can be
101automatically corrected by applying an explicit cast.)
102\item[How widely used:] Common.
103\end{description}
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