1 | // |
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2 | // Cforall Version 1.0.0 Copyright (C) 2015 University of Waterloo |
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3 | // |
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4 | // The contents of this file are covered under the licence agreement in the |
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5 | // file "LICENCE" distributed with Cforall. |
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6 | // |
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7 | // tupleAssign.c -- |
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8 | // |
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9 | // Author : Rob Schluntz |
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10 | // Created On : Tue Nov 15 17:24:32 2016 |
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11 | // Last Modified By : Rob Schluntz |
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12 | // Last Modified On : Tue Nov 15 17:27:28 2016 |
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13 | // Update Count : 3 |
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14 | // |
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15 | |
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16 | int main() { |
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17 | { |
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18 | // test multiple assignment and cascading assignment |
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19 | int u = 5, v = 6, x = 10, y = 11; |
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20 | [int, int] z = [100, 200]; |
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21 | |
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22 | // swap x, y and store the new [x, y] in [u, v] and in z; |
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23 | printf("u=%d v=%d x=%d y=%d z=[%d, %d]\n", u, v, x, y, z); |
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24 | z = [u, v] = [x, y] = [y, x]; |
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25 | printf("u=%d v=%d x=%d y=%d z=[%d, %d]\n", u, v, x, y, z); |
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26 | |
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27 | // shuffle elements -- v = z.0, z.0 = z.1, z.1 = u, u = v |
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28 | [v, z, u] = [z, u, v]; |
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29 | printf("u=%d v=%d z=[%d, %d]\n", u, v, z); |
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30 | |
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31 | // multiple assignment with tuple expression on right |
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32 | z = [111, 222]; |
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33 | [u, v] = [123, 456]; |
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34 | printf("u=%d v=%d z=[%d, %d]\n", u, v, z); |
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35 | } |
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36 | |
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37 | { |
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38 | // test mass assignment |
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39 | double d = 0.0; |
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40 | int i = 0; |
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41 | char c = '\0'; |
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42 | struct X { |
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43 | int z; |
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44 | } x; |
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45 | X ?=?(X * x, double d) {} |
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46 | [int, double, int] t; |
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47 | |
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48 | // no conversion from X to integral types, so this serves as a santiy |
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49 | // check that as long as this compiles, ?=?(_, x) is not generated. |
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50 | [t, x, d, i, c, x] = (double)-2153.12; |
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51 | printf("d=%lg i=%d c=%d t=[%d, %lg, %d]\n", d, i, (int)c, t); |
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52 | [x, c, i, d, x, t] = (double)-2153.12; |
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53 | printf("d=%lg i=%d c=%d t=[%d, %lg, %d]\n", d, i, (int)c, t); |
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54 | } |
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55 | } |
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56 | |
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57 | // Local Variables: // |
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58 | // tab-width: 4 // |
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59 | // End: // |
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