//
// Cforall Version 1.0.0 Copyright (C) 2015 University of Waterloo
//
// The contents of this file are covered under the licence agreement in the
// file "LICENCE" distributed with Cforall.
//
// tupleAssign.c --
//
// Author           : Rob Schluntz
// Created On       : Tue Nov 15 17:24:32 2016
// Last Modified By : Peter A. Buhr
// Last Modified On : Mon Mar  6 21:23:58 2017
// Update Count     : 34
//

#include <fstream>

int main() {
	{
		// test multiple assignment and cascading assignment
		int u = 5, v = 6, x = 10, y = 11;
		[int, int] z = [100, 200];

		// swap x, y and store the new [x, y] in [u, v] and in z;
		printf( "u=%d v=%d x=%d y=%d z=[%d, %d]\n", u, v, x, y, z );
		sout | "u=" | u | "v=" | v | "x=" | x | "y=" | y | "z=[" | z | "]" | endl;
		z = [u, v] = [x, y] = [y, x];
		printf( "u=%d v=%d x=%d y=%d z=[%d, %d]\n", u, v, x, y, z );
		sout | "u=" | u | "v=" | v | "x=" | x | "y=" | y | "z=[" | z | "]" | endl;

		// shuffle elements -- v = z.0, z.0 = z.1, z.1 = u, u = v
		[v, z, u] = [z, u, v];
		printf( "u=%d v=%d z=[%d, %d]\n", u, v, z );
		sout | "u=" | u | "v=" | v | "z=[" | z | "]" | endl;

		// multiple assignment with tuple expression on right
		z = [111, 222];
		[u, v] = [123, 456];
		printf( "u=%d v=%d z=[%d, %d]\n", u, v, z );
		sout | "u=" | u | "v=" | v | "z=[" | z | "]" | endl;
	}
	{
		// test mass assignment
		double d = 0.0;
		int i = 0;
		char c = '\0';
		struct X {
			int z;
		} x;
		X ?=?(X & x, double d) {}
		[int, double, int] t;

		// no conversion from X to integral types, so this serves as a santiy
		// check that as long as this compiles, ?=?(_, x) is not generated.
		[t, x, d, i, c, x] = (double)94.12;
		printf( "d=%lg i=%d c=%c t=[%d, %lg, %d]\n", d, i, (int)c, t );
		sout | "d=" | d | "i=" | i | "c=" | c | ' ' | "t=[" | t | "]" | endl;
		[x, c, i, d, x, t] = (double)-94.12;
		printf( "d=%lg i=%d c=%c t=[%d, %lg, %d]\n", d, i, c, t );
		sout | "d=" | d | "i=" | i | "c=" | c | ' ' | "t=[" | t | "]" | endl;
	}
}

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