\chapter{C Enumeration in \CFA}

\CFA supports legacy C enumeration using the same syntax for backwards compatibility. 
A C-style enumeration in \CFA is called a \newterm{C Enum}.
The semantics of the C Enum is mostly consistent with C with some restrictions.
The following sections detail all of my new contributions to C Enums.


\section{Enumerator Visibility}
\label{s:EnumeratorVisibility}

In C, unscoped enumerators present a \newterm{naming problem} when multiple enumeration types appear in the same scope with duplicate enumerator names.
\begin{cfa}
enum E1 { First, Second, Third, Fourth };
enum E2 { @Fourth@, @Third@, @Second@, @First@ }; $\C{// same enumerator names}$
\end{cfa}
There is no mechanism in C to resolve these naming conflicts other than renaming one of the duplicates, which may be impossible if the conflict comes from system include files.

The \CFA type-system allows extensive overloading, including enumerators.
Hence, most ambiguities among C enumerators are implicitly resolved by the \CFA type system, possibly without any programmer knowledge of the conflict.
In addition, C Enum qualification is added, exactly like aggregate field-qualification, to disambiguate.
\VRef[Figure]{f:EnumeratorVisibility} shows how resolution, qualification, and casting are used to disambiguate situations for enumerations @E1@ and @E2@.

\begin{figure}
\begin{cfa}
E1 f() { return Third; }				$\C{// overload functions with different return types}$
E2 f() { return Fourth; }
void g( E1 e );
void h( E2 e );
void foo() {							$\C{// different resolutions and dealing with ambiguities}$
	E1 e1 = First;   E2 e2 = First;		$\C{// initialization}$
	e1 = Second;   e2 = Second;			$\C{// assignment}$
	e1 = f();   e2 = f();				$\C{// function return}$
	g( First );   h( First );			$\C{// function argument}$
	int i = @E1.@First + @E2.@First;	$\C{// disambiguate with qualification}$
	int j = @(E1)@First + @(E2)@First;	$\C{// disambiguate with cast}$
}
\end{cfa}
\caption{Enumerator Visibility and Disambiguating}
\label{f:EnumeratorVisibility}
\end{figure}


\section{Enumerator Scoping}

A C Enum can be scoped, using @'!'@, so the enumerator constants are not projected into the enclosing scope.
\begin{cfa}
enum Week @!@ { Mon, Tue, Wed, Thu = 10, Fri, Sat, Sun };
enum RGB @!@ { Red, Green, Blue };
\end{cfa}
Now the enumerators \emph{must} be qualified with the associated enumeration type.
\begin{cfa}
Week week = @Week.@Mon;
week = @Week.@Sat;
RGB rgb = @RGB.@Red;
rgb = @RGB.@Blue;
\end{cfa}
% feature unimplemented
It is possible to toggle back to unscoped using the \CFA @with@ auto-qualification clause/statement (see also \CC \lstinline[language=c++]{using enum} in Section~\ref{s:C++RelatedWork}).
\begin{cfa}
with ( @Week@, @RGB@ ) {				$\C{// type names}$
	 week = @Sun@;						$\C{// no qualification}$
	 rgb = @Green@;
}
\end{cfa}
As in Section~\ref{s:EnumeratorVisibility}, opening multiple scoped enumerations in a @with@ can result in duplicate enumeration names, but \CFA implicit type resolution and explicit qualification/casting handle this localized scenario.


\section{Type Safety}

As in Section~\ref{s:Usage}, C's implicit bidirectional conversion between enumeration and integral type raises a safety concern.
In \CFA, the conversion is changed to unidirectional: an enumeration can be implicitly converted into an integral type, with an associated @safe@ conversion cost.
But an integral type cannot be implicitly converted into a C enumeration because the conversion cost is set to @infinity@.
\begin{cfa}
enum Bird { Penguin, Robin, Eagle };
enum Fish { Shark, Salmon, Whale };

int i = Robin;							$\C{// allow, implicitly converts to 1}$ 
enum Bird @bird = 1;@					$\C{// disallow }$ 
enum Bird @bird = Shark;@				$\C{// disallow }$ 
\end{cfa}
It is now up to the programmer to insert an explicit cast to force the assignment.
\begin{cfa}
enum Bird bird = @(Bird)@1;
enum Bird bird = @(Bird)@Shark 
\end{cfa}

Note, \CC has the same safe restriction~\cite[C.1.5.7.2]{C++} and provides the same workaround cast.
\begin{description}[parsep=0pt]
\item[Change:] \CC objects of enumeration type can only be assigned values of the same enumeration type.
In C, objects of enumeration type can be assigned values of any integral type.
Example:
\begin{cfa}
enum color { red, blue, green };
color c = 1;				$\C{// valid C, invalid \CC}$
\end{cfa}
\item[Rationale:] The type-safe nature of \CC.
\item[Effect on original feature:] Deletion of semantically well-defined feature.
\item[Difficulty of converting:] Syntactic transformation. (The type error produced by the assignment can be
automatically corrected by applying an explicit cast.)
\item[How widely used:] Common.
\end{description}

\begin{comment}
\begin{description}[parsep=0pt]
\item[Change:] In \CC, the type of an enumerator is its enumeration.
In C, the type of an enumerator is @int@.
Example:
\begin{cfa}
enum e { A };
sizeof(A) == sizeof(int)	$\C{// in C}$
sizeof(A) == sizeof(e)		$\C{// in \CC}$
/* and sizeof(int) is not necessary equal to sizeof(e) */
\end{cfa}
\item[Rationale:] In \CC, an enumeration is a distinct type.
\item[Effect on original feature:] Change to semantics of well-defined feature.
\item[Difficulty of converting:] Semantic transformation.
\item[How widely used:] Seldom. The only time this affects existing C code is when the size of an enumerator is
taken. Taking the size of an enumerator is not a common C coding practice.
\end{description}
\end{comment}